PdurStutter partition a value into n equal subdivisions

PdurStutter(stutterPattern, floatPattern)

A filter pattern designed for a stream of float durations.

subdivides each duration by each stutter and yields that value stutter times.

a stutter of 0 will skip the duration value, a stutter of 1 yields the duration value

unaffected.

(

a = PdurStutter(

Pseq(#[1,1,1,1,1,2,2,2,2,2,0,1,3,4,0],inf),

Pseq(#[0.5, 1, 2, 0.25,0.25],inf)

);

x = a.asStream;

100.do({ x.next.postln; });

)

(

SynthDef(\help_sinegrain, 

{ arg out=0, freq=440, sustain=0.05;

var env;

env = EnvGen.kr(Env.perc(0.01, sustain, 0.2), doneAction:2);

Out.ar(out, SinOsc.ar(freq, 0, env))

}).add;

)

(

a = PdurStutter(

Pseq(#[1,1,1,1,1,2,2,2,2,2,3,3,3,3,3,4,4,4,4,4],inf),

Pseq(#[0.5, 1, 2, 0.25,0.25],inf)

);

x = a.asStream;

Routine({

loop({

Synth.grain(\help_sinegrain, [\freq, 440]);

x.next.wait;

})

}).play(TempoClock.default);

)

(

a = PdurStutter(

Pseq(#[1,1,1,1,1,2,2,2,2,2,3,3,3,3,4,4,0,4,4],inf),

Pseq(#[0.5, 1, 2, 0.25,0.25],inf)

);

x = a.asStream;

Routine({

loop({

Synth.grain(\help_sinegrain, [\freq, 440]);

x.next.wait;

})

}).play(TempoClock.default);

)

Frequencies like being divided too.

(

a = PdurStutter(

Pseq(#[1,1,1,1,1,2,2,2,2,2,3,3,3,3,4,4,0,4,4],inf),

Pseq((80 + [ 0, 2, 3, 5, 7, 9, 10 ]).midicps ,inf)

);

x = a.asStream;

Routine({

loop({

Synth.grain(\help_sinegrain, [\freq, x.next.postln]);

0.25.wait

})

}).play(TempoClock.default);

)

-felix